SOLUTION: The perimeter of a rectangle is 28 ft. The length is 4 ft longer than the width. Find the dimensions. Write a system of linear equations and solve the resulting system. Let x be th

Algebra ->  Graphs -> SOLUTION: The perimeter of a rectangle is 28 ft. The length is 4 ft longer than the width. Find the dimensions. Write a system of linear equations and solve the resulting system. Let x be th      Log On


   



Question 688769: The perimeter of a rectangle is 28 ft. The length is 4 ft longer than the width. Find the dimensions. Write a system of linear equations and solve the resulting system. Let x be the length and y be the width.
Answer by Stitch(470) About Me  (Show Source):
You can put this solution on YOUR website!
Set-Up
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X = length
Y = width
Equation 1: 28+=+2X+%2B+2Y
Equation 2: X+=+Y+%2B+4
Solution:
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Plug (Y + 4) into equation 1 for X
Equation 1: 28+=+2X+%2B+2Y
28+=+2%28Y+%2B+4%29+%2B+2Y Simplify
28+=+2Y+%2B+8+%2B+2Y Combine like terms
28+=+4Y+%2B+8 Subtract 8 from both sides
20+=+4y Divide both sides by 4
highlight%285+=+Y%29
Now plug 5 into equation 2 for Y
Equation 2: X+=+Y+%2B+4
highlight%28X+=+9%29