SOLUTION: Find the center and radius of each circle. #1 (x+2)^2+y^2=16 #2 (x-1/2)^2+(y-1/2)^2=25 #3 (x-5)^2+y^2=68

Algebra ->  Graphs -> SOLUTION: Find the center and radius of each circle. #1 (x+2)^2+y^2=16 #2 (x-1/2)^2+(y-1/2)^2=25 #3 (x-5)^2+y^2=68      Log On


   

Question 647492: Find the center and radius of each circle.
#1 (x+2)^2+y^2=16
#2 (x-1/2)^2+(y-1/2)^2=25
#3 (x-5)^2+y^2=68
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the center and radius of each circle.
#1 (x+2)^2+y^2=16
It's %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2
so h = -2, k = 0, r = 4
--> %28x-2%29%5E2+%2B+y%5E2+=+4%5E2
Center @ (-2,0), r = 4
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Do these the same way.
#2 (x-1/2)^2+(y-1/2)^2=25
#3 (x-5)^2+y^2=68