Question 620590: Graph the quadratic equation by plotting points.
y=(x-3)^2
please include what points to plot. Thanks
Found 2 solutions by Alan3354, solver91311:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Graph the quadratic equation by plotting points.
y=(x-3)^2
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You plot as many points as you like.
Pick values for x and find y
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x = 0, y = 9
etc
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You can use Excel to make a table.
Plot the points, draw a curve thru them.
Answer by solver91311(24713)  (Show Source):
You can put this solution on YOUR website!
The function is in vertex form, so read the coordinates of the vertex directly and plot that. Coincidentally, the vertex is on the x-axis in this case, so you have your x-intercept also. If you don't know how to interpret the vertex form, Google "vertex form of a parabola" and pick the first thing that comes up.
Then substitute 0 for x and calculate the y-coordinate of the y-intercept. Plot that.
Figure out how far along the x-axis it is from the origin to the vertex, then go that same distance on the other side of the vertex to find a point with the same y-value as the y-intercept (symmetry)
Pick any other x-value (different from 0, the x-coordinate of the vertex, and the x-coordinate of the point symmetrical to the y-intercept) and calculate the value of the function for that x-value. Then use symmetry again to find a symmetrical point on the other side of the vertex.
That gives you 5 points which should be enough.
John
My calculator said it, I believe it, that settles it
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