SOLUTION: A graph of 2sin2x is intersected by the line with equation y=√3. Find the co-ordinates of B.

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Question 429956: A graph of 2sin2x is intersected by the line with equation y=√3. Find the co-ordinates of B.
Found 2 solutions by solver91311, htmentor:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Impossible to answer the question as posed with the information given. is a periodic function with a maximum value , therefore the graph of the constant function intersects the graph of infinitely many times. Since you did not provide a relative location for your point B, it is impossible to tell which of the intersecting points is the one you mean.

But that doesn't mean we are unable to determine anything about this problem. In order for the two graphs to intersect, the function values must be equal, hence:



Then



From the unit circle, recalling that sin is the -coordinate:



We can determine:



Or



From which we can derive



Or



Hence the set of all possible points B such that is

It is left to you to determine which of or you are going to use and an appropriate value for the integer . For example, if B is the point with the smallest positive value of , then use and


John

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Answer by htmentor(1343) About Me  (Show Source):
You can put this solution on YOUR website!
Not sure where the point "B" is, but to find the points of intersection, we set the two functions equal to one another:
%282%29sin%282x%29+=+sqrt%283%29
sin%282x%29+=+sqrt%283%29%2F2
One angle whose sin is sqrt%283%29%2F2 is 60 deg.
So 2x = 60 -> x = 30 deg.
Convert to radians:
30 deg * pi/180 deg = 0.5236
So one of the intersection points is (0.5236,sqrt%283%29)
graph%28300%2C300%2C-4%2C4%2C-3%2C3%2C2%2Asin%282%2Ax%29%2C3%5E0.5%29