SOLUTION: How do you get an equation for a parallel line that passes through a given point? example: (3,4); y=2x-7

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Question 229265: How do you get an equation for a parallel line that passes through a given point?
example: (3,4); y=2x-7

Found 2 solutions by rfer, drj:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
Plot the point and use the same slope as the first equation.
It becomes
y=2x-2

Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
How do you get an equation for a parallel line that passes through a given point?

example: (3,4); y=2x-7

Step 1. We note that parallel lines have the same slope.

Step 2. The slope-intercept form is given as y=mx+b where m is the slope and b is the y-intercept b at x=0 or point (0,b). Here, the slope of the give line is m=2 since y=2x-7. So now that we have the slope m=2, we need a line that has the same slope passing through (3,4)

Step 3. The slope m is given as

m=%28y2-y1%29%2F%28x2-x1%29

Step 4. Let (x1,y1)=(3,4) or x1=3 and y1=4. Let other point be (x2,y2)=(x,y) or x2=x and y2=y.

Step 5. Now we're given m=2. Substituting above values and variables in the slope equation m yields the following steps:

m=%28y2-y1%29%2F%28x2-x1%29

2=%28y-4%29%2F%28x-3%29

Step 6. Multiply (x-3) to both sides to get rid of denominators on both sides of equation.

2%28x-3%29=cross%28x-3%29%28y-4%29%2Fcross%28x-3%29

2x-6=y-4

Step 7. Now add 4to both sides of equation to solve for y.

2x-6%2B4=y-4%2B4

2x-2=y


Step 8. ANSWER: The equation is y=2x-2

Here's a graph below and note the slope and y-intercept at x=0 or point (0, 2) and the x-intercept at y=0 or at point (51/3, 0)and note it is consistent with the equation when substituting these

graph%28400%2C400%2C+-5%2C5%2C-5%2C5%2C+2x-2%29

Note: the above equation can be rewritten in standard form as

-2x%2By=-2

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J