SOLUTION: Please help me solve the following equation: (((f(x)=-x^2+4x+5)))
The question does not come out of the book. I am told to find the vertex, the line of symetry, the max or min v
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The question does not come out of the book. I am told to find the vertex, the line of symetry, the max or min v
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Question 210882: Please help me solve the following equation: (((f(x)=-x^2+4x+5)))
The question does not come out of the book. I am told to find the vertex, the line of symetry, the max or min value of the quadratic function and graph the function.
Thanks Missy Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! solve the following equation: (((f(x)=-x^2+4x+5)))
The question does not come out of the book. I am told to find the vertex, the line of symetry, the max or min value of the quadratic function and graph the function.
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f(x)=-x^2+4x+5
a = -1 ; b = 4 ; c = 5
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Max or Min value occurs when x = -b/2a = -4/(-2) = 2
f(2) = -(2)^2 + 4*2 + 5 = 9
Vertex occurs at (2,9)
The vertex is a max because "a" is negative
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The axis of symmetry is x = 2 because it must pass thru the vertex.
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Cheers,
Stan H.
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