SOLUTION: 13) Graph the inequality on a plane 5x+6y <= 30

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Question 146903: 13) Graph the inequality on a plane
5x+6y <= 30
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

5x%2B6y%3C=30 Start with the given inequality.


5x%2B6y=30 Replace the inequality sign with an equals sign.


6y=30-5x Subtract 5x from both sides.


y=%2830-5x%29%2F%286%29 Divide both sides by 6 to isolate y.


y=-%285%2F6%29x%2B5 Rearrange the terms.


So in order to plot 5x%2B6y%3C=30 or y%3C=-%285%2F6%29x%2B5 (which is the same thing), we need to plot the equation y=-%285%2F6%29x%2B5 first.
(note: if you need help with graphing, check out this solver)


+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C-%285%2F6%29x%2B5%29+ Graph of y=-%285%2F6%29x%2B5


Now plug in a test point (0,0) into the inequality y%3C=-%285%2F6%29x%2B5


y%3C=-%285%2F6%29x%2B5 Start with the given inequality.


0%3C=-%285%2F6%29%2A%280%29%2B5 Plug in x=0 and y=0


0%3C=5 Evaluate and simplify.


Since the inequality is true, this means that we shade the entire region that contains the point (0,0)


In other words, we simply shade the entire region that is below the line.


Graph of y%3C=-%285%2F6%29x%2B5 with the shaded region in green