SOLUTION: A two-digit number is 72 less than the number obtained by reversing the digits. Find the number.

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Question 1046935: A two-digit number is 72 less than the number obtained by reversing the digits. Find the number.
Found 2 solutions by josmiceli, advanced_Learner:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +t+ = the tens digit
Let +u+ = the units digit
--------------------------
+10t+%2B+u+=+10u+%2B+t+-+72+
+72+=+-9t+%2B+9u+
+-t+%2B+u+=+8+
The only thing that fits here is:
+t+=+1+
+u+=+9+
because if +u+ is 8 or less,
then t becomes zero or negative
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The number is 19
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check:
+10t+%2B+u+=+10u+%2B+t+-+72+
+10%2A1+%2B+9+=+10%2A9+%2B+1+-+72+
+19+=+91+-+72+
+19+=+19+
OK

Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!
guess work 91 and 19 difference is 72.
the number is 19
since 19=-72+91