Question 955362: AEC,DEB and AB are straight lines.the straights lines DA and CBF are parallel.angle ABF=90°,angle CEB=55°and angle ABE=25°.find angle ADE and find angle EAB ,explaining with reason
Answer by macston(5194)   (Show Source):
You can put this solution on YOUR website! Angle CEB and angle AEB lie on line AEC and since angle CEB=55 degrees, AEB=125 degrees. FBE and CBE are supplementary along line FBC.Angle FBE=angle FBA (90 degrees)+ angle ABE (25 degrees)=115 degrees, so angle CBE=65 degrees. Angle ADE is alternate to angle CBE, so angle ADE=65 degrees. In triangle ABE we have angle ABE=25 degrees, Angle AEB=125 degrees, so angle EAB=180-125-25=30 degrees
ANSWERS: ANGLE ADE=65 degrees and angle EAB=30 degrees.
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