SOLUTION: Given:m<1=3x-10 and m<2=2x+10 Prove: m<1=44 and m<2=46

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Question 840871: Given:m<1=3x-10 and m<2=2x+10
Prove: m<1=44 and m<2=46
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
From the solution, I'm guessing angles 1 and 2 are complementary.
3x-10%2B2x%2B10=90
5x=90
x=18
So then
3x-10=3%2818%29-10=54-10=44
2x%2B10=2%2818%29%2B10=36%2B10=46