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(1) ~C \/ D
(2) (~A \/ B) -> F
(3) ~B -> C
(4) ~F
Prove: D
I. ~F Given
II. ~(~A/\~B) By ~F -> ~(~A\/B), the contrapositive of (2)
III. ~(~A)/\~B ~(~A\/B) <-> ~(~A)/\~B DeMorgan's law
IV. A/\~B ~(~A)<-> A Negation of negation
V. ~B Conjunction IV
VI. C V, and (3), ~B -> C is given
VII. ~C \/ D given
VIII. C /\ (~C \/ D) Conjunction of VI with VII
IX. (C /\ ~C) \/ (C /\ D) Distributive law with VIII
X. false \/ (C /\ D) Conjunction of C with its negation is false
XI. C /\ D "false" is the identity for disjunction
XII. D Conjunction XI
Edwin