SOLUTION: If DE is perpendicular to AC, BF is perpendicular to AC, AF is congruent to CE, and DE is congruent to BF, Prove; a. triangle ADE is congruent to Triangle CBF b. DA is congruent to

Algebra ->  Geometry-proofs -> SOLUTION: If DE is perpendicular to AC, BF is perpendicular to AC, AF is congruent to CE, and DE is congruent to BF, Prove; a. triangle ADE is congruent to Triangle CBF b. DA is congruent to      Log On


   

Question 176459: If DE is perpendicular to AC, BF is perpendicular to AC, AF is congruent to CE, and DE is congruent to BF, Prove; a. triangle ADE is congruent to Triangle CBF b. DA is congruent to BC
Here is the picture http://img154.imageshack.us/my.php?image=67616727tk3.png sorry that it is fuzzy
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
The image is really hard to see. Does the figure look like this:



Note: let me know if any of the labels are off


I'll do the first part to get you going in the right direction:

a)

Prove triangle ADE is congruent to Triangle CBF

Here's a two column proof
StatementReason
1. Segment DE is perpendicular to Segment ACGiven
2. Segment BF is perpendicular to Segment ACGiven
3. Segment AF = Segment CEGiven
4. Segment DE = Segment BFGiven
5. Angle AED is a right angleDefinition of Perpendicular
6. Angle BFC is a right angleDefinition of Perpendicular
7. Angle BFC = Angle AEDAll right angles are congruent
8. Segment AF + Segment FC = Segment ACSegment Addition Postulate
9. Segment CE + Segment AE = Segment ACSegment Addition Postulate
9. Segment AF + Segment FC = Segment CE + Segment AESubstitution
10. Segment AF + Segment FC = Segment AF + Segment AESubstitution
11. Segment FC = Segment AEAddition Property of Equality
12. Triangle ADE = Triangle CBFSAS Property of Congruence