Question 146964This question is from textbook geometry
: Given:AB parallel to CD; BF bisects angle ABE; DG bisects angle CDB
Prove: BF is parallel to DG
This question is from textbook geometry
Answer by mangopeeler07(462)   (Show Source):
You can put this solution on YOUR website! You should draw this equation out to see what I am explaining easier (if you haven't already). Line DE contains line segment BE. Since AB and CD are parallel and they intersect with DE, then what ever angles they make with DE are congruent. Therefore angles ABE and CDE are congruent and corresponding, since they are in the same position on the parallel lines(above the horizontal line to the left of the vertical line). So since BF abd DG bisect angle ABE and angle CDE, congruent angles that are corresponding, they MUST be parallel to each other. That will always be true.
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