Question 1153816: In parallelogram ABCD, m∠ABD = 83°, m∠BDA = 34°, and m∠BCD =
°.
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20855)   (Show Source):
Answer by ikleyn(53763)  (Show Source):
You can put this solution on YOUR website! .
Tutor @MathLover1 is trying to solve the problem, even without reading it, so, she is WRONG.
In triangle ABD, you are given two angles, ABD and BDA.
Their sum is 83° + 34° = 117°.
Angle A (same as angle DAB) is, therefore, the supplementary angle to 117°,
so the measure of the angle DAB is 180° - 117° = 63°.
Angle BCD is the opposite angle in parallelogram ABCD to the angle DAB, so its measure is 63°. ANSWER
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