SOLUTION: You have two traingles that look like a bow and a trianle under it. Point C is the midpoint of both seg. AE and seg. DE, the ends of the bow. seg AB= x+1 seg AE= x^2 - 8 seg DE

Algebra ->  Geometry-proofs -> SOLUTION: You have two traingles that look like a bow and a trianle under it. Point C is the midpoint of both seg. AE and seg. DE, the ends of the bow. seg AB= x+1 seg AE= x^2 - 8 seg DE      Log On


   



Question 1150451: You have two traingles that look like a bow and a trianle under it.
Point C is the midpoint of both seg. AE and seg. DE, the ends of the bow.
seg AB= x+1
seg AE= x^2 - 8
seg DE= x^2 -x-7
seg BD= x+5
Is seg. BD congruent to seg AE?
Explain your awnser using geometric reasoning and support it with algebra.


Answer by ikleyn(52816) About Me  (Show Source):
You can put this solution on YOUR website!
.

If segments  AE  and  DE  are different  (and I sincerely believe in it),

            then the point  C   physically and geometrically  CAN  NOT   be their common midpoint.


Therefore, everything that follows makes no sense.


F A K E   problem.