You can
put this solution on YOUR website!
I will just give an outline of how to prove it. You
can write it up in a two-column proof.
A rhombus is a parallelogram with four congruent sides.
So, all sides of rhombus ABCD are congruent. That is
AB ≅ BC ≅ CD ≅ AD
We also know that the diagonals of a parallelogram bisect
each other. Since a rhombus is a parallelogram, it also has
this property.
Therefore BE ≅ DE, AE ≅ CE.
Therefore all 4 triangles are congruent by SSS.
Edwin