Question 88148:
Answer by malakumar_kos@yahoo.com(315) (Show Source):
You can put this solution on YOUR website!
a rectangular field is 4 times as long as it is wide . if the length is decreased by 10 in. and the width is increased by 2 in. the perimeter will be 80 in. find the dimensions of the original field
Let the width of the field be = b =x in.
the length of the field will be = l = 4x
the new length of the field be =L = 4x-10
the new width of the field be = B = x+2
the perimeter of the field is = p = 80
perimeter = 2(L+B)
p = 2(L+B)
80 = 2(4x-10+x+2)
80 = 2(5x-8)
80/2 = 5x-8
40 = 5x-8
5x = 40+8 = 48
x = 48/5 = 9.6 4x = 4.(9.6) = 38.4
length of the original field = 9.6 in
width of the original field = 38.4 in
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