SOLUTION: Right triangle ACB's altitude, CD, intersects AB at D. If AD = 3 and DB = 4, find the length of CD in simplest radical form.

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Question 724190: Right triangle ACB's altitude, CD, intersects AB at D. If AD = 3 and DB = 4, find the length of CD in simplest radical form.
Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
The altitude of a right triangle, dropped from the right angle, is a geometric mean of the two formed triangles. The part of the base of the short side / the altitude = the altitude / the part of the base of the long side.


In this problem AD/h = h/DB. ---> 3/h = h/4 ---> h%5E2=12 so h+=+sqrt%2812%29+=+sqrt%284%2A3%29+=+2%2Asqrt%283%29

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