SOLUTION: The length of a photograph is 4 in. greater than its width. The area of the photograph is 52 1/4 in.^2. What are the dimensions of the photograph?

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Question 536392: The length of a photograph is 4 in. greater than its width. The area of the photograph is 52 1/4 in.^2. What are the dimensions of the photograph?
Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
A=52 and 1/4=52.25=L*W


W = width.


L is 4 inches greater than W = W + 4.


W(W+4)=52.25


W^2 + 4W = 52.25


Subtract 52.25 from both sides.


W^2 + 4W - 52.25=0


This doesn't appear easy to factor, so use the quadratic equation.


=


%28-4+%2B-+sqrt%28+225+%29%29%2F%282%29=+%28-4+%2B-+15%29%2F2=


-19/2 or 11/2.


Throw away the negative answer, because a photo can't have negative dimensions.


W=11/2=5 and 1/2 inches.


L=W+4=9 and 1/2 inches

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