SOLUTION: the lenght of a regular lot is 6 yards longer than twice the width.if the perimeter is 288 yards,what are the lots of dimensions

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Question 281420: the lenght of a regular lot is 6 yards longer than twice the width.if the perimeter is 288 yards,what are the lots of dimensions
Answer by brucewill(101) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = width
Then 2x + 6 = length
We need 2 widths, and 2 lengths to equal 288.
2x+%2B+2%282x+%2B+6%29+=+288
2x+%2B+4x+%2B+12+=+288
6x+=+276
x+=+highlight%2846%29 width
2x+%2B+6+=+highlight%2898%29 length
Prove: 46+98+46+98=288.