SOLUTION: two congruent squares touch at one corner. One side of the square measures 3 cm. The triangle created from two of the common sides is a right triangle. Find the area (to the neares

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Question 263934: two congruent squares touch at one corner. One side of the square measures 3 cm. The triangle created from two of the common sides is a right triangle. Find the area (to the nearest tenth) of the entire figure.
Found 2 solutions by jim_thompson5910, CharlesG2:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Remember that the area of a triangle is A=bh%2F2. In this case, both the base and the height are 3 cm. Simply plug this value into b and h to find A.

Answer by CharlesG2(834) About Me  (Show Source):
You can put this solution on YOUR website!
two congruent squares touch at one corner. One side of the square measures 3 cm. The triangle created from two of the common sides is a right triangle. Find the area (to the nearest tenth) of the entire figure.
Area of one square = 3 cm * 3 cm = 9 cm^2
Area of both squares = 2 * 9 cm^2 = 18 cm^2
Area of Triangle = 1/2 * base * height = 1/2 * 3 cm * 3 cm= 3/2 * 3 = 9/2 = 4.5 cm^2
Area of entire figure = 18 cm^2 + 4.5 cm^2 = 22.5 cm^2