SOLUTION: a) A rectangular pen is build with one side against a barn. If 2100 m of fencing are used for the other three sides of the pen, what dimensions maximize the area of the pen? b) A

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: a) A rectangular pen is build with one side against a barn. If 2100 m of fencing are used for the other three sides of the pen, what dimensions maximize the area of the pen? b) A       Log On

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Question 1099767: a) A rectangular pen is build with one side against a barn. If 2100 m of fencing are used for the other three sides of the pen, what dimensions maximize the area of the pen?
b) A rancher plans to make four identical and adjacent rectangular pens against a barn, each with an area of 400m^2. What are the dimensions of each pen that minimize the amount of fence that must be used?

Found 3 solutions by josmiceli, KMST, ikleyn:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
(a)
Let +W+ = the length of the
side perpendicular to the barn
+2100+-+2W+ = the length of the side
parallel to the barn
-------------------------------
+A+=+W%2A%28+2100+-+2W+%29+
+A+=+-2W%5E2+%2B+2100W+
The formula for the W-value of the
maximum is:
+W%5Bmax%5D+=+-b%2F%282a%29+
+a+=+-2+
+b+=+2100+
+W%5Bmax%5D+=+-2100%2F%28+2%2A%28-2%29+%29+
+W%5Bmax%5D+=+525+
and
+2100+-+2W+=+2100+-+2%2A525+
+2100+-+1050+=+1050+
---------------------------------
The dimensions that maximize area are:
525 x 1050
-----------------------
check:
+A%5Bmax%5D+=+-2%2A%28W%5Bmax%5D%29%5E2+%2B+2100W%5Bmax%5D+
+A%5Bmax%5D+=+-2%2A525%5E2+%2B+2100%2A525+
+A%5Bmax%5D+=+-551250+%2B+1102500+
+A%5Bmax%5D+=+551250+ m2
and
+525%2A1050+=+551250+ m2
OK


Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
I see the first question as a quadratic function question,
although you need to know enough geometry to understand what a rectangle is.
The second question, looks more like a calculus question

a) The area y of that pen (in square meters) is y=x%282100-2x%29 .
You should recognize that as a quadratic function,
which graphs as a parabola, looking like this:
graph%28200%2C200%2C-0.1%2C0.9%2C-0.1%2C0.9%2C4x-5x%5E2%29 , with two zeros and a maximum exactly midway between them.
Re-writing it as y=2x%281050-x%29 shows you clearly that
y=0 for x=0 and x=1050 ,
y%3E0 in between, for 0%3Cx%3C1050 ,
and the maximum is at x=1050%2F2=525
The dimensions that maximize the area are
x=highlight%28525m%29 for the length of each of the two fencing sides attached to the barn wall, and
2100m-2x=2100m-2%28525m%29=2100m-1050m=highlight%281050m%29 for the length of of the fencing side parallel to the barn wall.

b) If we design something with four identical pens, like this:
, where x and y are lengths in m,
we know that x%2Ay=400m%5E2 <---> y=400%2Fx ,
and that makes the total length of fence needed, y , in m
y=5x%2B4%28400%2Fx%29=5x%2B1600%2Fx .
Maybe you are supposed to use a graphing calculator to find that the minimum for y happens at approximately x=17.888544 ,
and you could tell the farmer to use 5 17.9m length of fencing perpendicular to the barn wall,
attached to a 400m%5E2%2F%2217.9+m%22=approximately22.35m length parallel to the wall.

Using calculus, you would find that the derivative is
dy%2Fdx=5-1600%2Fx%5E2=5-%2840%2Fx%29%5E2 .
As dy%2Fdx%3C0 for -40%2Fsqrt%285%29%3Cx%3C40%2Fsqrt%285%29 ,
dy%2Fdx=0 for x=40%2Fsqrt%285%29 , and dy%2Fdx%3E0 for x%3E40%2Fsqrt%285%29 ,
the function decreases for x%3E0 to a minimum at x=40%2Fsqrt%285%29=approximately17.888544 , and increases for x%3E40%2Fsqrt%285%29 .

If there is another alternative approach, let me know.

Answer by ikleyn(52798) About Me  (Show Source):
You can put this solution on YOUR website!
.
For purely algebraic approach to solve such problems see the lessons
    - A farmer planning to fence a rectangular area along the river to enclose the maximal area
    - A rancher planning to fence two adjacent rectangular corrals to enclose the maximal area
in this site.


Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic "Finding minimum/maximum of quadratic functions".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.