SOLUTION: I'm not sure how to find the horizontal and vertical asymptote of this function {{{(sqrt(x^2-5x+6))/(x+1)}}}

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Question 800340: I'm not sure how to find the horizontal and vertical asymptote of this function %28sqrt%28x%5E2-5x%2B6%29%29%2F%28x%2B1%29
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
find the horizontal and vertical asymptote of this function %28sqrt%28x%5E2-5x%2B6%29%29%2F%28x%2B1%29
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To find the vertical asymptote, set the denominator=0, then solve for x
x+1=0
x=-1(vertical asymptote)
..
For the horizontal asymptote:
When the degree of the denominator=degree of numerator, as in this case, the horizontal asymptote is the x-axis. If you plot this curve on a graphing calculator, you will see the curve approaching the x-axis as x becomes more negative, starting from the left of the vertical asymptote.