You can put this solution on YOUR website! Let f(x)=3x-1, g(x)= 5/(2x+7) and h(x)=x^2+1
you want (fogoh)(x) = f[g[h(x)]]
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= f[g[(x^2+1)]]
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= f[5/2(x^2+1)+7)]
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= f[5/[2x^2+9]]
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= 3[5/(2x^2+9)]-1
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= 15/(2x^2+9) - 1
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= [15-(2x^2-9]]/(2x^2+9)
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= [-2x^2-24]/2x^2+9]