SOLUTION: For each fuction as defined that is one-to-one, (a) write an equation for the inverse function in the form y=f^-1(x), (b) graph f and f^-1 on the same axes, and (c) give the domain

Algebra ->  Functions -> SOLUTION: For each fuction as defined that is one-to-one, (a) write an equation for the inverse function in the form y=f^-1(x), (b) graph f and f^-1 on the same axes, and (c) give the domain      Log On


   

Question 3844: For each fuction as defined that is one-to-one, (a) write an equation for the inverse function in the form y=f^-1(x), (b) graph f and f^-1 on the same axes, and (c) give the domain and the range of f and f^-1. If the function is not one-to-one say so.
y=3x-4
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
this is a straight line --> it is one-to-one, so it has an inverse function.

Inverse: y=3x-4
y+4=3x
(y+4)/3 = x

The inverse function f%5E%28-1%29%28x%29+=+%28x%2B4%29%2F3

Domain and range? Well, both equations will allow any value in and can get any value out, so both functions have domain xeR and range xeR.

As for graphing them, if you are doing functions, you should be able to sketch a couple of straight lines --> look at my lessons on Linear Equations if you have trouble.

jon.