SOLUTION: Write a polynomial equation of least degree with roots of -3, -2i, 2i. 1.(x+3)(x + 2i)(x - 2i) = 0 2.x3-3x2+4x-12=0 3.(x+3)(x2+4)=0 4.x3+3x2+4x+12=0 With Explanation

Algebra ->  Functions -> SOLUTION: Write a polynomial equation of least degree with roots of -3, -2i, 2i. 1.(x+3)(x + 2i)(x - 2i) = 0 2.x3-3x2+4x-12=0 3.(x+3)(x2+4)=0 4.x3+3x2+4x+12=0 With Explanation      Log On


   

Question 1186466: Write a polynomial equation of least degree with roots of -3, -2i, 2i.
1.(x+3)(x + 2i)(x - 2i) = 0
2.x3-3x2+4x-12=0
3.(x+3)(x2+4)=0
4.x3+3x2+4x+12=0
With Explanation
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
1.(x+3)(x + 2i)(x - 2i) = 0 has roots -3, -2i, 2i

2.x3-3x2+4x-12=0 has roots 3, -2i, 2i

3.(x+3)(x2+4)=0 has roots -3, -2i, 2i

4. x3+3x2+4x+12=0 doesn't have any rational solutions.

So there are two correct answers, 1 and 3.  They both have solutions -3, -2i, 2i.

Edwin