SOLUTION: The equation of a circle in the xy plane is x^2+y^2+8x-10y=-5. What is the radius of the circle?
A)-6
B)6
C)36
D)None
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-> SOLUTION: The equation of a circle in the xy plane is x^2+y^2+8x-10y=-5. What is the radius of the circle?
A)-6
B)6
C)36
D)None
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Question 1119145: The equation of a circle in the xy plane is x^2+y^2+8x-10y=-5. What is the radius of the circle?
A)-6
B)6
C)36
D)None Answer by ikleyn(52815) (Show Source):
Perform completing the squares for x and y separately to transform the given equation to the standard equation of the circle:
x^2 + y^2 + 8x - 10y = -5
(x^2 + 8x) + (y^2 - 10y) = -5 <<<---=== first step - grouping
(x^2 + 8x + 16) + (y^2 - 10y + 25) = -5 + 16 + 25 <<<---=== identical transformations
+ = 36. <<<---=== complete the squares
You got the standard equation of the circle.
Answer. The radius of the circle is = 6.