SOLUTION: The equation of a circle in the xy plane is x^2+y^2+8x-10y=-5. What is the radius of the circle? A)-6 B)6 C)36 D)None

Algebra ->  Functions -> SOLUTION: The equation of a circle in the xy plane is x^2+y^2+8x-10y=-5. What is the radius of the circle? A)-6 B)6 C)36 D)None       Log On


   



Question 1119145: The equation of a circle in the xy plane is x^2+y^2+8x-10y=-5. What is the radius of the circle?
A)-6
B)6
C)36
D)None

Answer by ikleyn(52815) About Me  (Show Source):
You can put this solution on YOUR website!
.
Perform completing the squares for x and y separately to transform the given equation to the standard equation of the circle:


x^2 + y^2 + 8x - 10y = -5


(x^2 + 8x) + (y^2 - 10y) = -5                        <<<---=== first step - grouping


(x^2 + 8x + 16) + (y^2 - 10y + 25) = -5 + 16 + 25    <<<---=== identical transformations


%28x%2B4%29%5E2 + %28y-5%29%5E2 = 36.                                 <<<---=== complete the squares


You got the standard equation of the circle.


Answer.  The radius of the circle is  sqrt%2836%29 = 6.

Solved.