SOLUTION: 1) f(-x) = 2(-x) + 1 (simplify) 2) f(x+8) = 2(x+8) + 1 (simplify) 3) f(x)= x^5 + x^3 (determine if odd,even, or neither)

Algebra ->  Functions -> SOLUTION: 1) f(-x) = 2(-x) + 1 (simplify) 2) f(x+8) = 2(x+8) + 1 (simplify) 3) f(x)= x^5 + x^3 (determine if odd,even, or neither)       Log On


   

Question 1066043: 1) f(-x) = 2(-x) + 1 (simplify)
2) f(x+8) = 2(x+8) + 1 (simplify)
3) f(x)= x^5 + x^3 (determine if odd,even, or neither)


Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
1) f(-x) = 2(-x) + 1 = -2x+1
2) f(x+8) = 2(x+8) + 1 (simplify)
f(x+8) = 2(x+8) + 1 = 2x+16+1 = 2x+17
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3) f(x)= x^5 + x^3 (determine if odd,even, or neither)
f(-x) = -x^5 - x^3
-f(-x) = x^5 + x^3
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Since f(x) # f(-x) the function is not even.
Since f(x) = -f(-x) the function has origin symmetry. f is odd
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Cheers,
Stan H.
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