SOLUTION: The area of a rectangle is 180 square inches. The perimeter is 58 inches. What are the dimensions of the rectangle.
sixth grade student - doesn't know how to solve the problem
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Question 288983: The area of a rectangle is 180 square inches. The perimeter is 58 inches. What are the dimensions of the rectangle.
sixth grade student - doesn't know how to solve the problem Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! The area of rectangle = 180 cm^2
Perimeter = 58
L*W = 180
L= 180/W
Perimeter = 2L + 2W
Plug the value of L in the formula
2*(180/W) + 2W = 58
360 /W +2W= 58
360 +2W^2 / W = 58
360 +2W^2 = 58W
2W^2 -58W +360 =0
W^2 - 29w +180=0
W^2-20W-9W + 180=0
W(W-20)-9(W-20)=0
(W-9)(W-20)=0
w=9 or 20
