SOLUTION: The equation (y-2)^2/3^2-(x-2)^2/4^2=1 represents a hyperbola whose foci are (?,?) and (?,?) options for first set of ?'s a. (7,2) b. (2,7) c. (-2,7) options for second s

Algebra ->  Finance -> SOLUTION: The equation (y-2)^2/3^2-(x-2)^2/4^2=1 represents a hyperbola whose foci are (?,?) and (?,?) options for first set of ?'s a. (7,2) b. (2,7) c. (-2,7) options for second s      Log On


   

Question 1180217: The equation (y-2)^2/3^2-(x-2)^2/4^2=1 represents a hyperbola whose foci are (?,?) and (?,?)
options for first set of ?'s
a. (7,2)
b. (2,7)
c. (-2,7)
options for second set of ?'s
a. (2,-3)
b. (-3,2)
c. (-2,-3)
Answer by greenestamps(13334) About Me  (Show Source):
You can put this solution on YOUR website!


%28y-2%29%5E2%2F3%5E2-%28x-2%29%5E2%2F4%5E2=1

That given equation is in standard form: the hyperbola opens up and down; the center is (2,2); a=3 and b=4.

The distance from the center to each focus is c, where c^2=a^2+b^2.

That's all you need to determine the correct answer choices.