SOLUTION: 8x+3y+9z=29 5x+9y+7z=51 7x+9y+6z=61

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Question 1150181: 8x+3y+9z=29
5x+9y+7z=51
7x+9y+6z=61
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
8x+3y+9z=29
5x+9y+7z=51
7x+9y+6z=61
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If you want to solve for x, y & z you should say that.
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I would multiply the 1st eqn by 3 and then eliminate the y terms.