SOLUTION: a) A 15.1-L can is filled right up to the top with gasoline at 18.8 degrees Celsius. If the temperature of the gasoline climbs to 31.0 degrees Celsius, how much gasoline spills out

Algebra ->  Finance -> SOLUTION: a) A 15.1-L can is filled right up to the top with gasoline at 18.8 degrees Celsius. If the temperature of the gasoline climbs to 31.0 degrees Celsius, how much gasoline spills out      Log On


   

Question 1130919: a) A 15.1-L can is filled right up to the top with gasoline at 18.8 degrees Celsius. If the temperature of the gasoline climbs to 31.0 degrees Celsius, how much gasoline spills out of the can? Give your answer in L. Take the coefficient of volume expansion of gasoline to be 950 x 10-6 K-1. (Assume the volume of the can is unaltered by the change in temperature.)
b)A rod measures 24.0 cm at 247.0 K and 127.1 cm at 397.0 K. What is its coefficient of linear expansion? Give your answer in K-1.
Answer by ikleyn(52824) About Me  (Show Source):
You can put this solution on YOUR website!
.
(a)  The gasoline vvolume change due to the temperature change is 


     delta(V) = V * alpha * delta(T),


     where V is the initial volume of the gasoline in liters (given),  alpha is the the coefficient of volume expansion of gasoline (given)

     and delta(T) is the temperature difference (given).


     So, substitute  delta(V) = 15.1+%2A+950%2A10%5E%28-6%29+%2A+31 = 0.444 liters (approximately).    ANSWER


    This amount of the gasoline will go out from the can.

Solved.


(b)   Regarding (b), there is obvious error in the input data. 

     At given conditions, the length CAN NOT change so much.