SOLUTION: Assume that 32.9​% of people have sleepwalked. Assume that in a random sample of 1521 ​adults, 542 have sleepwalked.
a. Assuming that the rate of 32.9​% is​
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a. Assuming that the rate of 32.9​% is​
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Question 1125872: Assume that 32.9% of people have sleepwalked. Assume that in a random sample of 1521 adults, 542 have sleepwalked.
a. Assuming that the rate of 32.9% is correct, find the probability that 542 or more of the 1521 adults have sleepwalked.
b. Is that result of 542 or more significantly high?
c. What does the result suggest about the rate of 32.9%? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! a. 549/1521=36.1%
z=(p-phat)/sqrt(p*(1-p)/n)
=0.032/sqrt(0.329*0.671/1521)
=2.66
b. probability z>2.66 is 0.0039
This is about 2/5 ths of one percent, considered to be statistically significant.
c. That suggests that perhaps the quoted rate of 32.9% is too low.
