SOLUTION: Identify the graph: x2 + 12x + y2 + 22y + 121 = 0

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Question 1121381: Identify the graph: x2 + 12x + y2 + 22y + 121 = 0
Found 2 solutions by Alan3354, josgarithmetic:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Identify the graph: x2 + 12x + y2 + 22y + 121 = 0
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Use ^ for exponents.
x^2 + 12x + y^2 + 22y + 121 = 0
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Both x and y have a 2nd order term, and the signs are the same.
What do you think?

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Both the x and y are to power of 2.
Best first guess would be 'circle'.

x%5E2%2B12x%2By%5E2%2B22y%2B121=0
%28x%5E2%2B12x%2B36%29%2B%28y%2B11%29%5E2=0%2B36
%28x%2B6%29%5E2%2B%28y%2B11%29%5E2=6%5E2------------Now what do you think?



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CIRCLE with center (-6,-11) and radius 6