SOLUTION: Trains A and B are traveling in the smae direction on parallel tracks. Train A is traveling at 100 mph and train B is traveling 110 mph. Train A passes a station at 11:15am. If tra

Algebra ->  Expressions-with-variables -> SOLUTION: Trains A and B are traveling in the smae direction on parallel tracks. Train A is traveling at 100 mph and train B is traveling 110 mph. Train A passes a station at 11:15am. If tra      Log On


   

Question 454861: Trains A and B are traveling in the smae direction on parallel tracks. Train A is traveling at 100 mph and train B is traveling 110 mph. Train A passes a station at 11:15am. If train B passes the same station at 11:27am at what time will train B catch up to train A?
When will train B catch up with train A? __:__am or pm.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Trains A and B are traveling in the same direction on parallel tracks.
Train A is traveling at 100 mph and train B is traveling 110 mph.
Train A passes a station at 11:15am.
If train B passes the same station at 11:27am at what time will train B catch up to train A?
:
From the given information, we know that Train B is 12 min behind A at at 11:15 pm
therefore Train B is:
12%2F60 * 110 = 22 miles behind Train A at that time.
:
Let t = time required for Train B to catch Train A
:
Write a distance equation; dist = speed * time
:
Train B dist = Train A dist + 22 mi
110t = 100t + 22
110t - 100t = 22
10t = 22
t = 22%2F10
t = 2.2 hrs for B to catch A
:
Convert 2.2 hrs to hrs and minutes: 2 + .2(60) = 2 hr 12 min
:
Find the time from 11:15 pm:
11:15 + 2:12 = 1:27 pm, Train B catches Train A
:
:
We can check this by using relative speed between the trains, which is 10 mph
How long to cover 22 mi at 10 mph? 22%2F10 2.2 hrs which is 2 hrs 12 min