SOLUTION: Solve the System by Substitution: y=x+4 3x+y=16
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Question 23533
:
Solve the System by Substitution:
y=x+4
3x+y=16
Answer by
rapaljer(4671)
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y=x+4
3x+y=16
Substitute the y from the first equation into the second equation:
3x+ (_____)= 16
3x + (x+4) = 16
4x + 4 = 16
4x = 12
x=3
Substitute the x into the "y=" equation in order to find y:
y=x+4
y = 3+ 4= 7
Check in the second equation:
3x+y=16
3(3) + 7= 16
9+7=16
It checks!
R^2 at SCC