SOLUTION: a woman invested twice as much at 5% as she did at 6%. the total amount of interest she earned in 1 year from both accounts was $688. How much did she invest at each rate?
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-> SOLUTION: a woman invested twice as much at 5% as she did at 6%. the total amount of interest she earned in 1 year from both accounts was $688. How much did she invest at each rate?
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Question 218498: a woman invested twice as much at 5% as she did at 6%. the total amount of interest she earned in 1 year from both accounts was $688. How much did she invest at each rate? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! .06x+.05*2x=688
.06x+10x=688
.16x=688
x=688/.16
x=4,300 invested @ 6%
2*4,300=8,600 invested @ 5%
Proof:
.06*4,300+.05*8,600=688
258+430=688
688=688
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