SOLUTION: How many pounds of hamburger that costs $1.10 per pound must be mixed with 50 pounds of hamburger that costs $1.80 per pound to make a mixture that costs $1.30 per pound?
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Question 116287: How many pounds of hamburger that costs $1.10 per pound must be mixed with 50 pounds of hamburger that costs $1.80 per pound to make a mixture that costs $1.30 per pound?
I came up with 200. Please tell me if I am correct! Found 2 solutions by ptaylor, josmiceli:Answer by ptaylor(2198) (Show Source):
You can put this solution on YOUR website! CHECK MY APPROACH---I DIDN'T COME UP WITH THE SAME ANSWER AS YOU AND MY ANSWER SEEMS TO CHECK OUT
Let x=amount of hamburger that costs $1.10 per pound
Now we know that the cost of the hamburger before it's mixed together has to equal the cost of the hamburger after it's mixed together. So our equation to solve is:
$1.10x+$1.80*50=$1.30(50+x) simplify
$1.10x+$90=$65+$1.30x subtract $1.30x and also $90 from each side
$1.10x+$90-$90-$1.30x=$65-$90+1.30x-$1.30x collect like terms
-0.20x=-25 divide both sides by -0.20
x=125 lb--------------------amount of hamburger that cost $1.10 per lb
CK
125*1.10+$1.80*50=$1.30*175
137.5+90=227.5
227.5=227.5
You can put this solution on YOUR website! The formula is
( price per pound #1)(pounds #1) + (price per pound #2)(pounds #2)
equals (price per pound mixture)(pounds of mixture)
Let equal pounds of $1.10 hamburger pounds of #1.10 hamburger answer
check answer
OK
