SOLUTION: I have three questions... a> 4^x = 32 b> 5^x = 17 c> e^2x - 2e^x - 3 = 0

Algebra ->  Expressions-with-variables -> SOLUTION: I have three questions... a> 4^x = 32 b> 5^x = 17 c> e^2x - 2e^x - 3 = 0      Log On


   

Question 107593: I have three questions...
a> 4^x = 32
b> 5^x = 17
c> e^2x - 2e^x - 3 = 0
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
a> 4^x = 32
2^2x = 2^5
2x = 5
x = (5/2)
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b> 5^x = 17
xlog5 = log17
x = [log17]/[log5] = 1.76037...
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c> e^2x - 2e^x - 3 = 0
(e^x-3)(e^x+1= 0
e^x = 3 or e^x = -1
x = ln(3) or x=ln(-1)
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Only x=ln(3) is a solution as ln(-1) does not exist
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Cheers,
Stan H.