SOLUTION: (X^2y^2)^-1 (X to the second � y to the second) to the negative 1 Thanks!!
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Question 989286
:
(X^2y^2)^-1
(X to the second � y to the second) to the negative 1
Thanks!!
Answer by
CubeyThePenguin(3113)
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(x^2 * y^2)^(-1)
=