SOLUTION: Divide: (10x^3 -34x^2 - 59x -21)/(5x+3) I tried this one but am not sure if I am right. 10x^3 -34x^2 -59x -21/5x +3 -24x^5 -80x/8x = -24x^5-10x

Algebra ->  Exponents -> SOLUTION: Divide: (10x^3 -34x^2 - 59x -21)/(5x+3) I tried this one but am not sure if I am right. 10x^3 -34x^2 -59x -21/5x +3 -24x^5 -80x/8x = -24x^5-10x       Log On


   

Question 304644: Divide:
(10x^3 -34x^2 - 59x -21)/(5x+3)
I tried this one but am not sure if I am right.
10x^3 -34x^2 -59x -21/5x +3
-24x^5 -80x/8x = -24x^5-10x
Found 2 solutions by london maths tutor, Fombitz:
Answer by london maths tutor(243) About Me  (Show Source):
You can put this solution on YOUR website!
You could try long division.
Please email me for the working.
the answer: 2x%5E2+-+8x+-+7+

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Is your answer -24x%5E5-10x
If so, then no you're incorrect.
The degree of x in the solution should be lower than the degree of the original polynomial you started with like in the example,
x%5E5%2Fx%5E2=x%5E3
Use polynomial long division.
What do you need to multiply %285x%2B3%29 by to get 10x%5E3.
It would be 2x%5E2 since 2x%5E2%285x%29=10x%5E3.
So %282x%5E2%29 multiplied by (5x+3) would yield 10x%5E3%2B6x%5E2 .
%2810x%5E3+-34x%5E2+-59x+-21%29-%2810x%5E3%2B6x%5E2%29=-40x%5E2-59x-21
The next factor would be -8x which yields -40x%5E2-24x.
Subtracting then gives,
%28-40x%5E2-59x-21%29-%28-40x%5E2-24x%29=-25x-21.
Finally, the next multiplier is -5 and -5%285x%2B3%29=-25x-15
Subtracting,
-25x-21-%28-25x-15%29=-6
So then putting it all together,
%2810x%5E3+-34x%5E2+-59x+-21%29%2F%285x%2B3%29=2x%5E2-8x-5-6%2F%285x%2B3%29