SOLUTION: A particle P travel in a straight line so that its displacement x meters from a fixed point O is given by x=3t^2-4t^3+60, where t is the time in seconds measured from the start of
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Question 1154279: A particle P travel in a straight line so that its displacement x meters from a fixed point O is given by x=3t^2-4t^3+60, where t is the time in seconds measured from the start of the motion.Calculate
(a) the initial distance of P from O
(b) the magnitudes of the acceleration of P when it is instantaneously at rest,
(c)the average speed of P over the first two seconds Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! x=-4t^3+3t^2+60
t=0 initial distance is x=60
acceleration is 2nd derivative or x''=-24t+6, and x''(0)=6 m/sec^2
average speed is velocity (2)-velocity(1)/(2-1)
velocity is first derivative of position or -12t+6t+60
at t=1 it is 54
at t=2 it is 48
(48-64)/1=-16m/sec
