SOLUTION: How do I solve for x (3x−y)2+(x−5)2=0?

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Question 1113570: How do I solve for x (3x−y)2+(x−5)2=0?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
(3x - y)^2 + (x - 5)^2 = 0
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Use ^ (Shift 6) for exponents, as shown above.
9x^2 - 6xy + y^2 + x^2 - 10x + 25 = 0
10x^2 -10x - 6xy + y^2 + 25 = 0
10x^2 -x*(10 + 6y) + y^2 + 25 = 0
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x+=+%2810%2B6y%29%2F20+%2B+sqrt%28%2810%2B6y%29%5E2+-+40y%5E2+-+1000%29%2F20
and
x+=+%2810%2B6y%29%2F20+-+sqrt%28%2810%2B6y%29%5E2+-+40y%5E2+-+1000%29%2F20