SOLUTION: It’s been 12 yrs since my last Algebra class, and I’m in need of some refreshers. I’m supposed to solve and give my answer in a single reduced fraction, please help: {{{(x^2y/5x)*

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: It’s been 12 yrs since my last Algebra class, and I’m in need of some refreshers. I’m supposed to solve and give my answer in a single reduced fraction, please help: {{{(x^2y/5x)*       Log On


   

Question 8849: It’s been 12 yrs since my last Algebra class, and I’m in need of some refreshers. I’m supposed to solve and give my answer in a single reduced fraction, please help: %28x%5E2y%2F5x%29%2A+%285y%2Fx%5E2y%5E2%29

Answer by mrduffner(11) About Me  (Show Source):
You can put this solution on YOUR website!
Take it like any fractions you would multiply.
%28x%5E2y%2F5x%29%2A+%285y%2Fx%5E2y%5E2%29
Multiply the numerator by the numerator and the denominator by the denominator. First, you multiply the coefficients. In this case, an understood 1 in the first fraction times the 5 in the second fraction produces 5. Then you multiply the variables. x%5E2y%2Ay=x%5E2y%5E2 So our numerator is 5x%5E2y%5E2
Now we multiply the denominators. Coefficients first. 5 in the first denominator, and 1 in the second. Our coefficient part is 5. Then, the variables. x%2Ax%5E2y%5E2=x%5E3y%5E2 Our denominator is 5x%5E3y%5E2
Finally, we have our fraction. 5x%5E2y%5E2%2F5x%5E3y%5E2
Now we can cancel. The five and the five cancel each each other out, as do the y%5E2's, and we can cross out the x%5E2 from the bottom and simplify the top to only x. We are left with x%2F1, or x. I hope this helped.