You can put this solution on YOUR website! Note that (n+1)!=(n+1)(n)(n-1)(n-2)...(1)
But, n!=n(n-1)(n-2)...(1)
So, (n+1)!=n!(n+1)
Then,
3(n + 1)! / 5n!=3n!(n+1)/5n!
n! is common to the numerator and the denominator.
So,
3n!(n+1)/5n!=3(n+1)/5= (3n+3)/5
Power up,
HyperBrain!