SOLUTION: If x is not equal to 0, then x-2y/2y-x + 2y-x/x-2y The correct answer is -2 but I don't know how that the answer.

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Question 1184034: If x is not equal to 0, then
x-2y/2y-x + 2y-x/x-2y
The correct answer is -2 but I don't know how that the answer.
Found 2 solutions by Theo, greenestamps:
Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website!
it looks like the correct answer really is -2.

the expression is:

(x-2y) / (2y-x) + (2y-x) / (x-2y)

(x-2y) is equal to -1 * (2y-x)
(2y-x) is equal to -1 * (x-2y)

the expression becomes:

-(2y-x)/(2y-x) + -(x-2y)/(x-2y) which is equal to:

-1 + -1 which is equal to:

-2

Answer by greenestamps(13200) (Show Source):
You can put this solution on YOUR website!

Curiously, the expression you show is indeed equal to -2; and the expression you undoubtedly INTENDED to show is also equal to -2.

Here is the expression you show: "x-2y/2y-x + 2y-x/x-2y"

Here, on the other hand, is the expression you most probably meant: "(x-2y)/(2y-x)+(2y-x)/(x-2y)"

If you are working problems like this, your math knowledge should be great enough to know that proper use of parentheses is important...!