SOLUTION: ``Please someone help me because I keep trying this question and coming up with the wrong answer after I add it all up. Show all steps. Thanks If ln a=2 , ln b=3 , and ln c=5 ,

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: ``Please someone help me because I keep trying this question and coming up with the wrong answer after I add it all up. Show all steps. Thanks If ln a=2 , ln b=3 , and ln c=5 ,       Log On


   



Question 998720: ``Please someone help me because I keep trying this question and coming up with the wrong answer after I add it all up. Show all steps. Thanks
If ln a=2 , ln b=3 , and ln c=5 , evaluate the following:
d. (In c^-4)(In a/b^2)^4''.
(-4In5)(In(2)-In2(3))^4. = -40-(6^4)=-40-1296=1256. 1256 Was the ANSWER I GOT

Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52800) About Me  (Show Source):
You can put this solution on YOUR website!
.
If ln a=2 , ln b=3 , and ln c=5 , evaluate the following:
d. (In c^-4)(In a/b^2)^4''.
----------------------------------------------------------

ln%28c%5E%28-4%29%29 . ln%28%28a%2Fb%5E2%29%5E4%29 = %28-4%29 . ln%28c%29 . 4*ln%28a%2Fb%5E2%29 = (-4)*5 * 4* ( ln(a) - 2*ln(b) ) = (-4)*4*(2 -2*3) = . . .

Can you complete these calculations?


Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
``Please someone help me because I keep trying this question and coming up with the wrong answer after I add it all up. Show all steps. Thanks
If ln a=2 , ln b=3 , and ln c=5 , evaluate the following:
d. (In c^-4)(In a/b^2)^4''.
(-4In5)(In(2)-In2(3))^4. = -40-(6^4)=-40-1296=1256. 1256 Was the ANSWER I GOT
Sorry! That answer's incorrect.

ln a = 2; ln b = 3; and ln c = 5
ln_c%5E%28-+4%29%22%2A%22%28ln_%28a%2Fb%5E2%29%29%5E4 


ln_c%5E%28-+4%29 = ln_%281%2Fc%5E4%29 --------> ln_1+-+ln_c%5E4 ------> ln 1 – 4 * ln c -------> 0 – 4 * ln c -----> - 4 * ln c
%28ln_%28a%2Fb%5E2%29%29%5E4 = %28ln_a+-+ln_b%5E2%29%5E4 ------> %28ln_a+-+2+%2A+ln_b%29%5E4


ln_c%5E%28-+4%29%22%2A%22%28ln_%28a%2Fb%5E2%29%29%5E4 now becomes: 
%28-+4+%2A+ln_c%29+%2A+%28ln_a+-+2+%2A+ln_b%29%5E4

%28-+4+%2A+5%29+%2A+%282+-+2+%2A+3%29%5E4 ------- Substituting 2 for ln a; 3 for ln b; and 5 for ln c

-+20+%2A+%282+-+6%29%5E4

-+20+%2A+%28-+4%29%5E4

- 20(256), or highlight_green%28-+5120%29