SOLUTION: Solve e^2x-10e^x+24=0, it has two solutions. I am not sure how to solve it,but I tried to solve it and I will provide my step. Step 1 - use quadratic formula e^2x-10e^x+24=0

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Solve e^2x-10e^x+24=0, it has two solutions. I am not sure how to solve it,but I tried to solve it and I will provide my step. Step 1 - use quadratic formula e^2x-10e^x+24=0      Log On


   

Question 998703: Solve e^2x-10e^x+24=0, it has two solutions.
I am not sure how to solve it,but I tried to solve it and I will provide my step.
Step 1 - use quadratic formula
e^2x-10e^x+24=0
-b +/- sqrt(b^2-4ac)/2a
-[-10] +/- sqrt(-10^2-4(1)(24)/2(1)
10 +/- sqrt(4)/2
10 +/- 2/2
10 +/- 1
Answer by ikleyn(52790) About Me  (Show Source):
You can put this solution on YOUR website!
.
Solve e^2x-10e^x+24=0
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Factor

e%5E2x-10e%5Ex%2B24 = %28e%5Ex-4%29%2A%28e%5Ex-6%29.

Now the roots are

e%5Ex = 4   ----->  x = ln%284%29,     and

e%5Ex = 6   ----->  x = ln%286%29.