SOLUTION: I am trying to solve the problem: ln(x)-ln(2)=10
the way I thought this was supposed to be handled was:
1. ln(x)-ln(2)=10
2. ln(x-2)=10
3. ln(x-2)= e10
4. x-2=e10
5. x=e10+2
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-> SOLUTION: I am trying to solve the problem: ln(x)-ln(2)=10
the way I thought this was supposed to be handled was:
1. ln(x)-ln(2)=10
2. ln(x-2)=10
3. ln(x-2)= e10
4. x-2=e10
5. x=e10+2
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Question 998070: I am trying to solve the problem: ln(x)-ln(2)=10
the way I thought this was supposed to be handled was:
1. ln(x)-ln(2)=10
2. ln(x-2)=10
3. ln(x-2)= e10
4. x-2=e10
5. x=e10+2
however when I receive the answer 22026.50, this is shown to be incorrect. Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! From
ln(x)-ln(2)=10
I would combine logs first...
ln(x/2) = 10
then exponentiate
(x/2) = e^10
then multiply by 2
x = 2e^10 = 44052.9
