SOLUTION: log base 2 (5y+2) -1= log base 2 (1-2y)

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Question 981160: log base 2 (5y+2) -1= log base 2 (1-2y)
Answer by LinnW(1048) About Me  (Show Source):
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log base 2 (5y+2) -1= log base 2 (1-2y)
change since -1 = -log base 2(2), set -1 to -log base 2(2)
log base 2 (5y+2) - log base 2 (2)= log base 2 (1-2y)
because we know log(x) - log(y) = log(x/y) ,
log base 2 ((5y+2)/2) = log base 2 (1-2y)
so, (5y+2)/2 = 1-2y
multiply each side by 2
5y+2 = 2-4y
add 4y to each side
9y+2 = 2
add -2 to each side
9y = 0
y = 0
Checking by substitution in the original equation,
log base 2 (5(0)+2) -1= log base 2 (1-2(0))
log base 2 (2) -1 = log base 2(1)
or 1-1 = log base 2(1)
0 = 0